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Chemistry · Class 12 · Chapter 9

Coordination Compounds

Werner to CFT in one pass: nomenclature, isomerism, VBT hybridisation, crystal field splitting, colour and magnetism, and every application NTA has asked for.

NEET 20272–3 questions/yearHighest return per hour

01Chapter map & Werner's theory

Coordination Compounds reliably gives 2–3 NEET questions, and they are unusually predictable: one on IUPAC naming or oxidation state, one on hybridisation / magnetic moment, one on isomerism or CFT colour. Almost none of it is calculation — it is rules applied carefully, which makes it the highest return-per-hour chapter in Inorganic.

Priority 1

  • IUPAC nomenclature + oxidation number of the central metal
  • VBT: hybridisation, inner vs outer orbital, μ = √n(n+2)
  • CFT: Δo vs Δt, high/low spin, colour
  • Isomerism: counting geometrical and optical isomers

Priority 2

  • Werner's theory, primary/secondary valency, ionisable chloride
  • Ambidentate and chelating ligands, chelate effect
  • Metal carbonyls, synergic bonding, EAN
  • Applications: extraction, qualitative analysis, biology

Werner's theory (1893)

ComplexOld nameIons in solutionAgNO3 gives
CoCl3·6NH3 = [Co(NH3)6]Cl3luteo (yellow)43 AgCl
CoCl3·5NH3 = [Co(NH3)5Cl]Cl2purpureo (purple)32 AgCl
CoCl3·4NH3 = [Co(NH3)4Cl2]Clpraseo (green) / violeo (violet)21 AgCl
CoCl3·3NH3 = [Co(NH3)3Cl3]0 (non-electrolyte)no precipitate

NEET hook

Conductivity and AgCl-precipitate questions are pure counting: only the ions outside the square bracket are ionisable. Molar conductance rises in the order 0 < 1:1 < 1:2 < 1:3 electrolyte, so the 6NH3 complex conducts the most.

02Ligands, denticity & coordination number

ClassMeaningExamples
Monodentateone donor atomNH3, H2O, CN, Cl, CO, NO2
Bidentatetwo donor atomsen (H2NCH2CH2NH2), ox2−, gly, dmg, acac
Polydentateseveral donor atomsEDTA4− (hexadentate, 2 N + 4 O)
Ambidentatetwo possible donor atoms, only one binds at a timeNO2 (nitrito-N / nitrito-O), SCN (thiocyanato-S / isothiocyanato-N), CN
Chelatingbi/polydentate forming a ring with the metalen, ox, EDTA — 5- and 6-membered rings are most stable

Where it goes wrong

Oxidation-state slips come from forgetting that en, NH3, H2O and CO are neutral while ox, gly, dmg and EDTA carry charge (ox = −2, gly = −1, dmg = −1 each, EDTA = −4). Write the charge under each ligand before you solve.

03IUPAC nomenclature — the six rules

  1. Cation first, anion second, exactly as in simple salts.
  2. Inside the sphere, ligands are named alphabetically (ignore the multiplying prefix), then the metal.
  3. Anionic ligands end in -o: chlorido, cyanido, hydroxido, oxalato, sulphato, nitrito-N (M–NO2) / nitrito-O (M–ONO). Neutral ligands keep their name except aqua (H2O), ammine (NH3), carbonyl (CO), nitrosyl (NO).
  4. Prefixes di, tri, tetra; use bis, tris, tetrakis when the ligand name already contains di/tri or is complicated (e.g. bis(ethane-1,2-diamine), tris(ethane-1,2-diamine)).
  5. Oxidation state of the metal in Roman numerals in brackets right after its name, no space.
  6. If the complex ion is an anion, the metal takes the suffix -ate and often its Latin name: ferrate (Fe), cuprate (Cu), argentate (Ag), aurate (Au), stannate (Sn), plumbate (Pb), but cobaltate, nickelate, chromate, manganate, platinate.
FormulaIUPAC name
[Co(NH3)5(CO3)]Clpentaamminecarbonatocobalt(III) chloride
[Pt(NH3)2Cl(NH2CH3)]Cldiamminechlorido(methanamine)platinum(II) chloride
K3[Fe(CN)6]potassium hexacyanidoferrate(III)
K3[Al(C2O4)3]potassium trioxalatoaluminate(III)
[CoCl2(en)2]Cldichloridobis(ethane-1,2-diamine)cobalt(III) chloride
[Ni(CO)4]tetracarbonylnickel(0)
[Cr(NH3)3(H2O)3]Cl3triamminetriaquachromium(III) chloride
[Ag(NH3)2][Ag(CN)2]diamminesilver(I) dicyanidoargentate(I)

Right content, wrong arrangement

This is exactly the error pattern that has cost marks across your papers. Alphabetical order is by the ligand name, not the prefix: in [Co(NH3)4Cl2]+ it is tetraamminedichlorido — a before c. But in [CoCl2(en)2]+ it is dichloridobis(ethane-1,2-diamine) — c before e.

04Isomerism

Structural isomerism

TypeWhat swapsStandard pair
Ionisationligand inside ↔ counter ion outside [Co(NH3)5SO4]Br (gives AgBr)  /  [Co(NH3)5Br]SO4 (gives BaSO4)
Hydrate (solvate)water inside ↔ water of crystallisation [Cr(H2O)6]Cl3 violet / [Cr(H2O)5Cl]Cl2·H2O grey-green / [Cr(H2O)4Cl2]Cl·2H2O dark green
Linkagewhich atom of an ambidentate ligand binds [Co(NH3)5(NO2)]2+ nitrito-N (yellow) / nitrito-O (red)
Coordinationligands exchange between a complex cation and a complex anion [Co(NH3)6][Cr(CN)6] / [Cr(NH3)6][Co(CN)6]

Stereoisomerism

Isomer explorer pick a formula type

Counting table — memorise this row by row

TypeGeometryGeometricalOpticalTotal
MA2B2square planar2 (cis, trans)02
MABCDsquare planar303
MA4B2octahedral2 (cis, trans)02
MA3B3octahedral2 (fac, mer)02
M(AA)2B2octahedral2cis only (d, l)3
M(AA)3octahedral0d, l2
MA2B2C2octahedral51 pair6

05Valence bond theory — hybridisation & magnetism

Method, in order: (1) find the oxidation state, (2) write the dn configuration of the ion, (3) decide whether the ligand is strong or weak, (4) pair up if strong, (5) count vacant orbitals and name the hybridisation, (6) count unpaired electrons for μ.

μ = √[n(n + 2)] BM   n = 1 → 1.73  |  2 → 2.83  |  3 → 3.87  |  4 → 4.90  |  5 → 5.92
CNHybridisationShapeExampleSpin
6d2sp3 (inner orbital, low spin)octahedral[Co(NH3)6]3+, [Fe(CN)6]3−diamagnetic / 1 unpaired
6sp3d2 (outer orbital, high spin)octahedral[CoF6]3−, [FeF6]3−, [Ni(NH3)6]2+paramagnetic
4dsp2square planar[Ni(CN)4]2−, [Pt(NH3)2Cl2], [Cu(NH3)4]2+usually diamagnetic
4sp3tetrahedral[NiCl4]2−, [Ni(CO)4], [MnCl4]2−[NiCl4]2− has 2 unpaired
5sp3d / dsp3trigonal bipyramidal[Fe(CO)5], [CuCl5]3−

The pair NEET loves

[Ni(CN)4]2− vs [NiCl4]2−. Both are Ni(II), d8. CN is strong → the two unpaired 3d electrons pair up, one 3d orbital is freed, hybridisation is dsp2, square planar, diamagnetic (μ = 0). Cl is weak → no pairing, sp3, tetrahedral, paramagnetic (μ = 2.83 BM). Same metal, same oxidation state, opposite answers — the ligand decides.

Limitations of VBT (frequently a one-line question)

  • Gives no quantitative account of magnetic data and no explanation of colour.
  • Does not predict whether a 4-coordinate complex will be tetrahedral or square planar; the choice of inner vs outer orbital is assumed, not derived.
  • Cannot explain thermodynamic or kinetic stability, and ignores excited-state properties.

06Crystal field theory

Ligands are treated as point negative charges; the electrostatic field they create splits the degenerate d orbitals. The energy gap is Δo (octahedral) or Δt (tetrahedral).

Octahedral: t2g (dxy, dyz, dzx) at −0.4Δo; eg (dx²−y², d) at +0.6Δo
Tetrahedral: the order inverts — e below t2, and Δt = (4/9) Δo, always high spin

Spectrochemical series — learn the ends

I < Br < SCN < Cl < S2− < F < OH < C2O42− < H2O < NCS < edta4− < NH3 < en < CN < CO

Memory line: I Browse Some Class Sites For OH Oxford Water, Never Edta… NH3 < en < CN < CO. The last four are what actually get asked.

Live: crystal field splitting choose dn, geometry and field strength

Limitations of CFT

  • Treats the metal–ligand bond as purely ionic and ignores covalent overlap.
  • Cannot explain why CO and CN — neutral or weakly charged — are the strongest field ligands, while the small, highly charged OH is weak. (Ligand field / MO theory with π-back bonding does.)

07Colour, d–d transitions & magnetic behaviour

Visible light promotes an electron from t2g to eg (a d–d transition). The complex absorbs that wavelength and we see the complementary colour.

Δo = hc/λ  ⇒  strong ligand → large Δ → short λ absorbed → observed colour shifts towards yellow/orange
Live: absorbed wavelength → colour you actually see slide through the spectrum
Complex ionColour observedNote
[Ti(H2O)6]3+violetd1, absorbs around 500 nm (green-yellow)
[Cu(H2O)4]2+blued9
[Ni(H2O)6]2+green→ [Ni(en)3]2+ is violet: stronger ligand, bigger Δ
[Co(NH3)6]3+yellow-oranged6 low spin, diamagnetic
[Fe(CN)6]4−yellowd6 low spin, diamagnetic
[Fe(CN)6]3−red-brownd5 low spin, μ = 1.73 BM

Answer in one line

Diamagnetic ⇒ all electrons paired, μ = 0, weakly repelled by a magnetic field. Paramagnetic ⇒ unpaired electrons, attracted. Ask only: how many unpaired electrons, then μ = √n(n+2).

08Stability, chelate effect & metal carbonyls

Syllabus gap

Stability constants and the bonding in metal carbonyls are trimmed in the rationalised NCERT text but continue to appear in NEET-level questions. Treat this section as compulsory extra reading.

Stability

M + 4L ⇌ ML4,   β4 = [ML4] / [M][L]4  — larger β means a more stable complex

Metal carbonyls & synergic bonding

M C O σ: C lone pair → M π*: M d-electrons → CO (back bonding)
Two arrows in opposite directions — that picture is the whole of synergic bonding.

09Importance & applications

Biological systems

  • Haemoglobin — Fe(II) porphyrin; carries O2. CO binds far more strongly, which is why it is poisonous.
  • ChlorophyllMg porphyrin; photosynthesis.
  • Vitamin B12 (cyanocobalamin) — Co; the only metal-containing vitamin.
  • Carboxypeptidase-A and carbonic anhydrase — Zn enzymes.

Industry & medicine

  • cis-platin, [Pt(NH3)2Cl2] — anti-tumour; the trans isomer is inactive.
  • EDTA — treats lead poisoning; also estimates hardness of water (Ca2+, Mg2+).
  • d-penicillamine and desferrioxamine — chelation therapy for copper and iron overload.
  • Wilkinson's catalyst [(Ph3P)3RhCl] — hydrogenation of alkenes; Ziegler–Natta for polymerisation.

Extraction of metals

  • Ag and Au: leached with dilute NaCN in air to give [Ag(CN)2], then displaced by Zn.
  • Ni — Mond's process: impure Ni + CO at about 330–350 K → volatile [Ni(CO)4], which decomposes at 450–470 K to pure Ni.
  • Purification through complex formation is the common thread.

Analytical chemistry

  • Ni2+ + dmg in ammoniacal medium → bright red precipitate (square planar, H-bonded rings).
  • Cu2+ + excess NH3 → deep blue [Cu(NH3)4]2+.
  • Fe3+ + SCN → blood-red [Fe(SCN)]2+.
  • Photography: unexposed AgBr is dissolved by hypo as [Ag(S2O3)2]3−.
  • Electroplating from [Ag(CN)2] gives a smooth, adherent deposit.

10Last-hour recall sheet & rapid drill

If the question says…Answer instantly
[Co(NH3)6]3+d6, d2sp3, inner orbital, low spin, diamagnetic, μ = 0
[CoF6]3−d6, sp3d2, outer orbital, high spin, 4 unpaired, μ = 4.90 BM
[Fe(CN)6]3− / [FeF6]3−d5: 1 unpaired (1.73 BM) / 5 unpaired (5.92 BM)
[Ni(CO)4]Ni(0), d10, sp3, tetrahedral, diamagnetic
[Ni(CN)4]2−Ni(II) d8, dsp2, square planar, diamagnetic
[NiCl4]2−Ni(II) d8, sp3, tetrahedral, 2 unpaired, 2.83 BM
[Cr(NH3)6]3+d3, d2sp3, 3 unpaired, 3.87 BM (spin state same either way)
Strongest / weakest field ligandCO strongest, I weakest
Δt in terms of Δo4/9 Δo; tetrahedral is always high spin
Optically active octahedral example[Co(en)3]3+; cis-[CoCl2(en)2]+
EDTA denticityhexadentate: 2 N + 4 O
Colourless ionsd0 and d10: Sc3+, Ti4+, Zn2+, Cu+, Ag+, Cd2+
Rapid drill — 10 one-liners tap to reveal

Final checklist

  1. Did I count donor atoms for the coordination number, not ligand molecules?
  2. Did I give the charge of every ligand before finding the oxidation state?
  3. Alphabetical order by ligand name, ignoring di/tri/tetra?
  4. Is the metal named as an -ate anion because the complex ion is negative?
  5. For d4–d7 only, did I check the ligand strength before deciding the spin state?
  6. μ = √n(n+2) uses n = unpaired electrons, not the total d count.