Test: 23-Aug-26, Sun 11:30 · Prepared for Aamirah Fathima
1 · p-Block Group 18 — Noble Gases
P2 · 1–2 Q, pure recall
Family facts worth exactly one mark each
Members: He, Ne, Ar, Kr, Xe, Rn (Rn is radioactive, from ²²⁶Ra decay). Og is synthetic.
Configuration ns²np⁶; helium alone is 1s².
Argon is the most abundant noble gas in the atmosphere (≈0.934% by volume).
Helium is the second most abundant element in the universe after hydrogen; on Earth it comes from natural gas / radioactive α-decay.
All are monatomic gases, colourless, odourless, sparingly soluble in water.
Highest ionisation enthalpy in each period; He has the highest IE of all elements.
Electron gain enthalpy is large and positive — they resist gaining electrons.
Only London dispersion forces → very low melting and boiling points, increasing down the group with atomic size.
He has the lowest boiling point of any known substance (4.2 K); below 2.2 K it becomes a superfluid (helium-II).
Atomic radii are the largest in each period because van der Waals radii are quoted, not covalent radii.
Uses — asked as matching questions
Gas
Uses
He
Filling balloons/airships (non-inflammable, low density); He–O₂ mixture for deep-sea divers (low solubility in blood avoids bends); cryogenics and superconducting magnets in NMR/MRI; inert atmosphere for welding
Ne
Discharge tubes and neon signs, fluorescent bulbs, botanical gardens/warning signals
Ar
Inert atmosphere in high-temperature metallurgy and arc welding; filling electric bulbs with N₂; laboratory inert atmosphere
Kr, Xe
Light bulbs, flash lamps, Xe in bactericidal lamps; Kr used in the older definition of the metre
Rn
Radiotherapy for cancer
Trap — abundance vs universe
"Most abundant noble gas" needs you to check whether the question says atmosphere (→ argon)
or universe (→ helium). Both statements are true in their own context; the option list will
contain the other one as a distractor.
2 · Xenon Compounds — structure & hybridisation
P1 · nearly guaranteed
History and reactivity
Neil Bartlett (1962) noticed that O₂ and Xe have almost the same ionisation enthalpy.
Having made O₂⁺[PtF₆]⁻, he reacted Xe with PtF₆ and obtained Xe⁺[PtF₆]⁻ — the first noble gas compound.
Only Xe (and to a small extent Kr, as KrF₂) forms real compounds, and only with the two most
electronegative elements: fluorine and oxygen. Xe is chosen because it has the lowest ionisation
enthalpy among the non-radioactive members.
Preparation of the fluorides — the ratios are the question
Product
Xe : F₂
Conditions
XeF₂
2 : 1
673 K, 1 bar
XeF₄
1 : 5
873 K, 7 bar
XeF₆
1 : 20
573 K, 60–70 bar
Structures — the master table
Compound
Bond pairs
Lone pairs
Hybridisation
Shape
XeF₂
2
3
sp³d
Linear
XeF₄
4
2
sp³d²
Square planar
XeF₆
6
1
sp³d³
Distorted octahedral
XeO₃
3
1
sp³
Pyramidal
XeOF₄
5
1
sp³d²
Square pyramidal
XeO₂F₂
4
1
sp³d
See-saw
XeO₄
4
0
sp³
Tetrahedral
Gold lobes are lone pairs — they decide the shape, the fluorines only decide the name.
Hydrolysis — the reaction chain NEET asks about
Partial: XeF₆ + H₂O → XeOF₄ + 2HFFurther: XeF₆ + 2H₂O → XeO₂F₂ + 4HFComplete: XeF₆ + 3H₂O → XeO₃ + 6HFXeF₄ + H₂O → XeO₃ + Xe + O₂ + HF (disproportionation)2XeF₂ + 2H₂O → 2Xe + 4HF + O₂ · XeF₆ + MF → M⁺[XeF₇]⁻ (M = Na, K, Rb, Cs)XeF₂, XeF₄, XeF₆ are all powerful fluorinating agents and are readily hydrolysed even by traces of water.
Memory hook — count the waters1 water → XeOF₄, 2 waters → XeO₂F₂, 3 waters → XeO₃. Each water swaps two F for one O.
3 · Electrochemistry — Cells & EMF
P1 · 3–4 Q
Galvanic (voltaic) cell
Electrolytic cell
Energy
chemical → electrical
electrical → chemical
Reaction
spontaneous, ΔG < 0, Ecell > 0
non-spontaneous, ΔG > 0
Anode
negative, oxidation
positive, oxidation
Cathode
positive, reduction
negative, reduction
Example
Daniell cell, dry cell
electrolysis, electroplating, recharging
Trap — the sign of the electrodes flips, oxidation does not
In both cells: anode = oxidation, cathode = reduction. Only the +/− labels swap.
Never memorise "anode is negative" alone.
Cell notation & salt bridge
Zn(s) | Zn²⁺(1 M) ‖ Cu²⁺(1 M) | Cu(s) E°cell = +1.10 V
Anode on the left (oxidation), cathode on the right, single bar = phase boundary, double bar = salt bridge.
Salt bridge (KCl, KNO₃, NH₄NO₃ in agar-agar): completes the circuit and maintains electrical
neutrality in both half-cells, preventing accumulation of charge. The chosen salt has cation and anion
of nearly equal transport numbers. It also minimises the liquid junction potential.
Electrons travel through the wire; ions travel through the salt bridge. Anode mass falls, cathode mass rises.
Standard electrode potential & SHE
SHE: Pt(s) | H₂(1 bar) | H⁺(1 M), 298 K, E° = 0.00 V by definition.
All E° values in NCERT are reduction potentials. More positive E° → stronger oxidising agent, greater tendency to be reduced.
F₂/F⁻ = +2.87 V (strongest oxidising agent in the table); Li⁺/Li = −3.05 V (strongest reducing agent).
E° is an intensive property — do not multiply it when you multiply the half-equation.
E°cell = E°cathode − E°anode = E°right − E°left (both as reduction potentials)ΔG° = −nFE°cell · ΔG° = −2.303RT log Kc · E°cell = (0.059/n) log Kc at 298 K
Trap — n in ΔG° = −nFE°
n is the number of electrons actually transferred in the balanced cell reaction, not the charge on
one ion. For Zn + Cu²⁺ → Zn²⁺ + Cu, n = 2. For Cr₂O₇²⁻ → 2Cr³⁺, n = 6.
Aamirah — this n-factor slip has cost marks on more than one paper. Balance the electrons first, then substitute.
4 · Nernst Equation — live calculator
P1
Ecell = E°cell − (2.303RT/nF) log Q → at 298 K: E = E° − (0.059/n) log QFor Zn + Cu²⁺ ⇌ Zn²⁺ + Cu: E = E° − (0.059/2) log([Zn²⁺]/[Cu²⁺])At equilibrium Ecell = 0 and Q = Kc → the cell is dead.Solids and pure liquids do not appear in Q. Only the products of the cell reaction over the reactants.
Daniell cell — change the concentrations
E°cell = +1.10 V, n = 2. Watch how weakly E depends on concentration — a ten-fold change moves it by only 0.0295 V.
log Q
—
E cell
—
ΔG
—
Spontaneous?
—
Memory hook — which way does E move?
Increase the reactant concentration (Cu²⁺) → reaction is pushed forward → E rises.
Increase the product (Zn²⁺) → E falls. Le Chatelier, translated into volts.
5 · Conductance of Electrolytic Solutions
P1
Conductance G = 1/R (siemens, S = ohm⁻¹ = mho)Conductivity κ = G × (l/A) = G × cell constant (S m⁻¹ or S cm⁻¹)Cell constant = l/A (m⁻¹) — found using a standard KCl solutionMolar conductivity Λm = κ/c = κ × 1000 / M (S cm² mol⁻¹, with c in mol L⁻¹)Degree of dissociation α = Λm/Λ°m · Ka = cα²/(1 − α)Kohlrausch: Λ°m = ν₊λ°₊ + ν₋λ°₋
On dilution
Conductivity κ
Molar conductivity Λm
Trend
decreases
increases
Reason
fewer ions per unit volume
more ions per mole (greater dissociation / less interionic attraction)
Λm versus √c — the shape that identifies the electrolyte
Strong electrolytes give a straight line you can extrapolate. Weak electrolytes shoot up near infinite dilution and cannot be extrapolated.
Kohlrausch's law of independent migration — what it is used for
Λ°m of weak electrolytes, which cannot be measured directly: Λ°(CH₃COOH) = Λ°(CH₃COONa) + Λ°(HCl) − Λ°(NaCl)
Degree of dissociation α = Λm/Λ°m
Dissociation constant Ka = cα²/(1 − α)
Solubility of sparingly soluble salts (AgCl, BaSO₄): S = κ × 1000 / Λ°m
Trap — unit conversion
Λm = κ × 1000/c only when κ is in S cm⁻¹ and c in mol L⁻¹, giving S cm² mol⁻¹.
If κ is in S m⁻¹ and c in mol m⁻³, then Λm = κ/c in S m² mol⁻¹.
1 S m² mol⁻¹ = 10⁴ S cm² mol⁻¹. Half the marks lost in this topic are unit slips, not concept slips.
6 · Electrolysis & Faraday's Laws
P1 · numerical
First law: m ∝ Q → m = Z I t (Z = electrochemical equivalent)Second law: for the same Q, m ∝ equivalent mass1 faraday F = 96487 ≈ 96500 C mol⁻¹ = charge of 1 mole of electronsmoles deposited = It / (n × F) · mass = (It/96500) × (M/n)n here is the number of electrons per ion in the electrode half-reaction.
Half reaction
n
1 F deposits / liberates
Ag⁺ + e⁻ → Ag
1
1 mol Ag = 108 g
Cu²⁺ + 2e⁻ → Cu
2
½ mol Cu = 31.75 g
Al³⁺ + 3e⁻ → Al
3
⅓ mol Al = 9 g
2H⁺ + 2e⁻ → H₂
2
½ mol H₂ = 11.2 L at STP
2H₂O → O₂ + 4H⁺ + 4e⁻
4
¼ mol O₂ = 5.6 L at STP
Products of electrolysis — preferential discharge
The species with the higher reduction potential is reduced at the cathode; the one with the
lower reduction potential (easier to oxidise) is oxidised at the anode.
Molten NaCl → Na at cathode, Cl₂ at anode.
Aqueous NaCl → H₂ at cathode (water is reduced in preference to Na⁺), Cl₂ at anode
(because of the overpotential of oxygen, chlorine wins even though water has the more favourable E°).
Aqueous CuSO₄ with Pt electrodes → Cu at cathode, O₂ at anode.
Aqueous CuSO₄ with Cu electrodes → Cu deposited at cathode, Cu dissolved at anode (electro-refining).
Dilute H₂SO₄ → H₂ and O₂ in a 2:1 volume ratio.
7 · Batteries, Fuel Cells & Corrosion
P2 · recall
Cell
Anode
Cathode
Electrolyte
EMF / note
Dry (Leclanché) cell primary
Zn container
graphite rod surrounded by MnO₂ + C
moist paste of NH₄Cl + ZnCl₂
≈1.5 V, falls with use; not rechargeable
Mercury cell primary
Zn–Hg amalgam
HgO + carbon
paste of KOH + ZnO
1.35 V, constant — hearing aids, watches
Lead storage battery secondary
Pb
PbO₂ on a lead grid
38% H₂SO₄
2 V per cell; PbSO₄ forms at both electrodes on discharge; recharged by reversing the current
Ni–Cd cell secondary
Cd
NiO₂ / Ni(OH)₂
KOH
longer life than lead storage, costlier
H₂–O₂ fuel cell
H₂ at porous carbon
O₂ at porous carbon
concentrated aqueous KOH
catalysts Pt / Pd / finely divided metal; efficiency ~70%; product is water; used in Apollo space programme
Corrosion of iron — an electrochemical cell on the metal surface
Anode (impure/strained spot): Fe → Fe²⁺ + 2e⁻, E° = −0.44 V
Cathode: O₂ + 4H⁺ + 4e⁻ → 2H₂O, E° = +1.23 V (H⁺ from dissolved CO₂/acid)
Fe²⁺ is further oxidised by atmospheric O₂ to Fe₂O₃·xH₂O — hydrated ferric oxide, rust
Requires both moisture and oxygen; accelerated by salt and acidity
Prevention: painting/greasing, galvanising with zinc, cathodic protection with a sacrificial
Mg or Zn block (a metal with more negative E°), alloying to stainless steel
Secondary valence = coordination number; satisfied by ligands; non-ionisable; directional — it fixes the geometry.
Ligands inside the coordination sphere are written in [ ] and do not give a precipitate with AgNO₃.
Complex
Ionisable Cl⁻
Mol of AgCl with excess AgNO₃
Ions in solution
[Co(NH₃)₆]Cl₃
3
3
4
[Co(NH₃)₅Cl]Cl₂
2
2
3
[Co(NH₃)₄Cl₂]Cl
1
1
2
[Co(NH₃)₃Cl₃]
0
0
0 (non-electrolyte)
Ligand vocabulary
Type
Meaning
Examples
Monodentate
one donor atom
NH₃, H₂O, Cl⁻, CN⁻, CO, NO₂⁻
Bidentate
two donor atoms
en (ethane-1,2-diamine), ox (oxalate C₂O₄²⁻), gly
Hexadentate
six donor atoms
EDTA⁴⁻ (2 N + 4 O)
Ambidentate
two possible donor atoms, only one binds at a time
NO₂⁻ (via N = nitrito-N, via O = nitrito-O), SCN⁻ (thiocyanato-S / isothiocyanato-N), CN⁻
Chelate
a ring formed by a polydentate ligand — extra stability (chelate effect)
[Co(en)₃]³⁺, EDTA complexes
Trap — ambidentate ≠ bidentate
An ambidentate ligand has two possible donor atoms but uses only one — it is monodentate in
practice and gives linkage isomerism. A bidentate ligand uses both and forms a chelate ring.
Applications — the named-complex list
Complex / compound
Metal
Role
Chlorophyll
Mg
photosynthesis
Haemoglobin
Fe
oxygen transport
Vitamin B₁₂ (cyanocobalamin)
Co
anti-pernicious anaemia
cis-[Pt(NH₃)₂Cl₂] — cisplatin
Pt
anti-cancer (trans isomer is inactive)
EDTA complexes
Ca, Mg
water hardness estimation, lead poisoning treatment
Wilkinson's catalyst [(Ph₃P)₃RhCl]
Rh
hydrogenation of alkenes
[Ag(CN)₂]⁻, [Au(CN)₂]⁻
Ag, Au
extraction (Mac Arthur–Forrest cyanide process)
[Ni(CO)₄]
Ni
Mond process for pure nickel
Na₂[Fe(CN)₅NO], Fe₄[Fe(CN)₆]₃
Fe
qualitative analysis — Prussian blue
9 · IUPAC Nomenclature of Complexes
P1
The rules, in order
Cation first, anion second — whether or not the complex is the cation.
Inside the sphere: ligands first (alphabetical order), then the metal.
Prefixes di, tri, tetra for simple ligands; bis, tris, tetrakis for ligands whose names
already contain a numeral (en, ox, and anything in brackets). Prefixes are ignored when alphabetising.
Anionic ligands end in -o (chlorido, cyanido, hydroxido, oxalato, sulphato, nitrito-N).
Neutral ligands keep their names, with four exceptions: aqua (H₂O), ammine (NH₃), carbonyl (CO),
nitrosyl (NO).
Oxidation state of the metal in Roman numerals in parentheses.
If the complex is an anion, the metal name takes -ate — and often the Latin stem:
ferrate (Fe), cuprate (Cu), argentate (Ag), aurate (Au), plumbate (Pb), stannate (Sn), nickelate (Ni), cobaltate (Co).
The name of the whole complex ion or molecule is written as one word.
Memory hook — oxidation state in three seconds
Overall charge = (metal O.S.) + (sum of ligand charges). In K₃[Fe(CN)₆]: the complex ion is 3−,
six CN⁻ contribute 6−, so Fe = +3. Neutral ligands (NH₃, H₂O, CO, en) contribute zero.
ligands swapped between a complex cation and a complex anion
[Co(NH₃)₆][Cr(CN)₆] / [Cr(NH₃)₆][Co(CN)₆]
B · Stereoisomerism
Formula type
Geometry
Geometrical isomers
Optical activity
MA₂B₂
square planar
2 — cis and trans
none (has a plane of symmetry)
MA₂B₂
tetrahedral
0 — all positions adjacent
none
MA₄B₂
octahedral
2 — cis and trans
none
MA₃B₃
octahedral
2 — fac and mer
none
[M(AA)₂X₂]
octahedral
2 — cis and trans
cis is optically active (d and l); trans is inactive
[M(AA)₃]
octahedral
—
optically active — d and l forms, e.g. [Co(en)₃]³⁺
MABCD
tetrahedral
—
optically active (no symmetry)
Tetrahedral complexes show no geometrical isomerism — every pair of positions is adjacent.
11 · VBT, CFT & Magnetic Moment — live splitting diagram
P1 · the money question
Spin-only magnetic moment μ = √[n(n + 2)] BM, n = number of unpaired electronsn = 1 → 1.73 n = 2 → 2.83 n = 3 → 3.87 n = 4 → 4.90 n = 5 → 5.92 BMΔt = (4/9) Δo → tetrahedral complexes are always high spinCFSE (octahedral) = (−0.4 nt2g + 0.6 neg) Δo
Crystal field splitting — build the configuration yourself
Choose the d-electron count, the geometry, and the ligand strength. The boxes fill by Hund's rule when the field is weak, and pair up when the field is strong.
Unpaired e⁻
—
μ (spin only)
—
Magnetism
—
CFSE
—
Spectrochemical series — learn the two ends
I⁻ < Br⁻ < SCN⁻ < Cl⁻ < S²⁻ < F⁻ < OH⁻ < C₂O₄²⁻ < H₂O < NCS⁻ < edta⁴⁻ < NH₃ < en < NO₂⁻ < CN⁻ < COLeft = weak field, small Δ, high spin. Right = strong field, large Δ, low spin.
CO and CN⁻ are the strongest; I⁻ is the weakest.
VBT — inner vs outer orbital complexes
Inner orbital (low spin)
Outer orbital (high spin)
Hybridisation
d²sp³ — uses (n−1)d
sp³d² — uses nd
Ligand
strong field (CN⁻, NH₃, NO₂⁻, CO)
weak field (F⁻, Cl⁻, H₂O)
Magnetism
usually diamagnetic / fewer unpaired e⁻
paramagnetic, maximum unpaired e⁻
Example
[Co(NH₃)₆]³⁺, [Fe(CN)₆]³⁻
[CoF₆]³⁻, [Fe(H₂O)₆]³⁺
Tetrahedral → sp³ (4 coordination). Square planar → dsp², always low spin; d⁸ metals
like Ni²⁺ with strong ligands, and Pt²⁺/Pd²⁺ always. [Ni(CN)₄]²⁻ is square planar and diamagnetic;
[NiCl₄]²⁻ is tetrahedral and paramagnetic — a favourite comparison.
Trap — colour
Colour arises from d–d transitions, so a complex is coloured only when the d-subshell is
partially filled. d⁰ (Sc³⁺, Ti⁴⁺) and d¹⁰ (Zn²⁺, Cu⁺, Ag⁺, Cd²⁺) complexes are colourless.
The colour you see is the complementary colour of the light absorbed.
Limitations you should be able to stateVBT does not explain colour, does not predict the magnitude of magnetic data quantitatively,
and gives no reason for the existence of strong and weak ligands.
CFT treats the bond as purely ionic, ignoring the covalent character shown by the spectrochemical
series, and cannot explain why CO is such a strong-field ligand (that needs synergic π back-bonding).
12 · Haloalkanes & Haloarenes — portion subtopics only
P1 · 14 Q section
A · Classification
Basis
Classes
Number of halogens
mono, di (gem-dihalide = same carbon, e.g. ethylidene chloride; vic-dihalide = adjacent carbons, e.g. ethylene dichloride), tri (CHCl₃), poly
Memory hook — one carbon decides everything
If X sits on the sp² carbon (vinyl, aryl) it is sluggish. If X sits one carbon away
from the unsaturation (allyl, benzyl) it is super-reactive. Same atoms, opposite behaviour.
B · Nomenclature
Structure
Common name
IUPAC name
CH₃Cl
Methyl chloride
Chloromethane
(CH₃)₂CHBr
Isopropyl bromide
2-Bromopropane
(CH₃)₃CCl
tert-Butyl chloride
2-Chloro-2-methylpropane
CH₂Cl₂
Methylene chloride
Dichloromethane
CHCl₃
Chloroform
Trichloromethane
CCl₄
Carbon tetrachloride
Tetrachloromethane
CHI₃
Iodoform
Triiodomethane
CH₃CHCl–CH₃
—
2-Chloropropane
CH₂Cl–CH₂Cl
Ethylene dichloride
1,2-Dichloroethane
CH₃CHCl₂
Ethylidene chloride
1,1-Dichloroethane
C₆H₅CH₂Br
Benzyl bromide
1-(Bromomethyl)benzene
Numbering rules: halogens are treated as substituents — they never get priority over a principal
functional group. Lowest locant goes to the substituent set as a whole; when there is a tie, alphabetical
order decides (bromo before chloro before iodo before methyl).
C · Nature of the C–X bond
Halogen is more electronegative than carbon → the bond is polar covalent, with
C carrying δ+ and X carrying δ−. The δ+ carbon is the site attacked by nucleophiles — this single
fact explains the whole chapter.
Property
Order
Why
C–X bond length
C–F < C–Cl < C–Br < C–I
halogen size increases down the group
C–X bond enthalpy
C–F > C–Cl > C–Br > C–I
longer bond = weaker bond
Reactivity towards nucleophiles
R–I > R–Br > R–Cl > R–F
weakest bond breaks first — opposite to electronegativity
Dipole moment
CH₃Cl > CH₃F > CH₃Br > CH₃I
μ = charge × distance — F's high electronegativity is offset by its very short bond
Boiling point
RI > RBr > RCl > RF
larger molecule = stronger dispersion forces
Boiling point among isomers
straight chain > branched
branching reduces surface contact
Density
RI > RBr > RCl
all haloalkanes are denser than water except some chlorides/fluorides
Trap — the dipole moment orderCH₃Cl > CH₃F, not the other way round. Fluorine is the most electronegative, but the C–F bond is
so short that the charge × distance product is smaller. This exact ordering appears every couple of years.
D · Electrophile and nucleophile
Nucleophile
Electrophile
Meaning
"nucleus loving" — electron rich, donates an electron pair
"electron loving" — electron deficient, accepts an electron pair
Charge
anion or neutral with a lone pair
cation or neutral with an incomplete octet
Lewis classification
Lewis base
Lewis acid
Attacks
the δ+ carbon
the δ− / π-electron-rich site
Examples
OH⁻, CN⁻, NH₃, H₂O, RO⁻, RS⁻, X⁻, R⁻
H⁺, NO₂⁺, Cl⁺, BF₃, AlCl₃, R₃C⁺, carbonyl carbon
In a haloalkane, the carbon is the electrophilic centre and the halogen leaves as the nucleophile X⁻.
Ambident nucleophiles like CN⁻ can attack through C (giving nitriles with KCN, which is ionic) or through
N (giving isocyanides with AgCN, which is covalent).
E · Nucleophilicity and leaving group ability
Basicity = affinity for H⁺ (thermodynamic). Nucleophilicity = affinity for carbon (kinetic). They are not the same thing.
Down a group in a protic solvent (water, alcohol): I⁻ > Br⁻ > Cl⁻ > F⁻ —
the small F⁻ is heavily solvated by hydrogen bonding and is caged.
In a polar aprotic solvent (DMSO, DMF, acetone) the order reverses to F⁻ > Cl⁻ > Br⁻ > I⁻,
because there is no H-bond cage and basicity takes over.
For the same attacking atom, the conjugate base is the better nucleophile: OH⁻ > H₂O, RO⁻ > ROH, NH₂⁻ > NH₃.
Leaving group ability: the weaker the base, the better the leaving group.I⁻ > Br⁻ > Cl⁻ ≫ F⁻. OH⁻, NH₂⁻ and OR⁻ are strong bases and therefore very poor leaving groups —
which is why alcohols must be protonated (to leave as H₂O) before substitution.
Trap — a good nucleophile is not always a good leaving group
F⁻ is a strong base: a poor leaving group but a good nucleophile in aprotic media.
I⁻ is a weak base: an excellent leaving group and also a good nucleophile in protic media
(which is why iodide catalyses many substitutions).
F · Why vinyl and aryl halides barely react
Same resonance idea, opposite consequence — depending on whether X is on the sp² carbon or next to it.
Four reasons vinyl and aryl halides resist nucleophilic substitution
Resonance. A lone pair on the halogen is delocalised into the π system, giving the C–X bond
partial double-bond character. It is shorter and stronger, so it will not break easily.
Hybridisation. The carbon is sp², which has 33% s-character (vs 25% for sp³). It holds the
bonding electrons more tightly, so the bond is shorter and stronger and the carbon is less δ+.
Unstable intermediate. An SN1 route would need a vinyl or phenyl carbocation, which is
very high in energy because the empty orbital cannot be stabilised by the π system.
Steric / electronic repulsion. The π electron cloud repels the incoming nucleophile,
blocking backside attack, so SN2 is also shut down.
Aryl halides can be substituted, but only under forcing conditions
(e.g. NaOH at 623 K and 300 atm) or when strong electron-withdrawing groups sit ortho/para to the
halogen — as in 2,4-dinitrochlorobenzene, which reacts under mild conditions. A meta-nitro group does
not help, because the negative charge of the intermediate cannot reach it.
G · Why allyl and benzyl halides react so fast
Both form resonance-stabilised carbocations on ionisation, so the SN1 route is unusually easy.
The allyl cation is stabilised over two carbons; the benzyl cation is delocalised into the whole ring
(and further stabilised in di- and triphenylmethyl systems).
Trap — testing with AgNO₃
Benzyl and allyl halides give an immediate precipitate of AgX with alcoholic AgNO₃ at room
temperature; 3° alkyl halides react quickly, 1° halides only on warming, and vinyl/aryl halides give no
precipitate at all. This is the standard distinguishing test in assertion–reason questions.
Scope reminder for this paper
Only the seven listed subtopics are in the 14-question Haloalkanes block. Full SN1/SN2 mechanism
stereochemistry, elimination (Saytzeff), Wurtz/Fittig/Sandmeyer reactions and polyhalogen compounds are
not listed — read them only if time remains after the four chapters above.
60-Second Recall — read this in the car
Most abundant noble gasatmosphere Ar · universe He